2x^2+37x-72=0

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Solution for 2x^2+37x-72=0 equation: 



2x^2+37x-72=0

a = 2; b = 37; c = -72;
Δ = b2-4ac
Δ = 372-4·2·(-72)
Δ = 1945
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(37)-\sqrt{1945}}{2*2}=\frac{-37-\sqrt{1945}}{4}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(37)+\sqrt{1945}}{2*2}=\frac{-37+\sqrt{1945}}{4}
$

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